Week 3: Solving by Factoring

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 9x + 20 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 7x + 12 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 13x + 12 = 0

• x = -1, x = -12
• x = -1, x = -24
• x = -2, x = -6
• x = -2, x = -12

Tags

CCSS.HSA-REI.B.4B

Solve:
x² - 49 = 0

• x = -7, x = 7
• x = -7
• x = 7
• x = -7, x = 1

Tags

CCSS.HSA-REI.B.4B

Solve

2x² - 3x - 2 = 0

• x = 1, x = -1

• x = -1/2, x = 2

• x = 1/2, x = 2

• x = 1/2, x = 1

Solve
 3x² + 5x - 12 = 0

• x = -4/3, x = 3
• x = 4/3, x = -3
• x = -1, x = 4
• x = 1, x = -4

Tags

CCSS.HSA-REI.B.4B

Solve for X:

(x-5)(x+6)=0

• x = {5,5 }

• x = { -5,-5 }

• x = { -5,-6 }

• x = {5,-6 }

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA.REI.B.4

Which equation matches these solutions? x = {5, -7}

• (x+5)(x-7) = 0

• (x-5)(x+7) = 0

• (x+5)(x+7) = 0

• (x-5)(x-7) = 0