Torques Basics - Level 2 Physics NCEA

Torques Basics - Level 2 Physics NCEA

12th Grade

10 Qs

quiz-placeholder

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Torques Basics - Level 2 Physics NCEA

Torques Basics - Level 2 Physics NCEA

Assessment

Quiz

Physics

12th Grade

Medium

Created by

Gail Glaister

Used 86+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

A force of 20 N is used 0.25m away from the center of the nut (pivot). Calculate the torque used.

2

5

4

10

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

A force of 120 N is used 40 cm away from the center of the nut (pivot). Calculate the torque used.

42

45

48

50

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

F1 is 30 N acting 2 m away from the pivot. F2 is 10 N, how far away from the pivot does it act if the object is in equilibrium?

2 m

4 m

6 m

8 m

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The elephants weight force is 4000N acting 0.5 m away from the pivot. How much force is the mouse using at 0.70 m from the pivot to keep the seesaw in equilibrium?

2857.14

2800

4376.34

2000

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

W1 has a weight of 220 N acting 0.6m away from the pivot. How far does W2 whose weight is 180 N need to sit for the see saw to be in equilibrium.

0.3 m

0.73 m

0.5m

0.83 m

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The red cars total mass is 750 kg acting 0.24 m from the pivot. The yellow car is acting 0.57 m from the pivot. Calculate the weight of the yellow car when the seesaw is in equilibrium.

315.78 kg

5482.46 N

298 N

3094.74 N

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The red cars total mass is 450 kg acting 0.2 m from the pivot. The yellow car is acting 0.55 m from the pivot when the see saw is in equilibrium. Calculate the yellow cars mass.

163.64 kg

200 kg

163.64 N

3094.74 N

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