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Literal Equations Day 1 Practice

Literal Equations Day 1 Practice

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSA.CED.A.4, HSA.REI.B.3, 7.EE.A.1

Standards-aligned

Created by

Ashley Rideout

Used 11+ times

FREE Resource

3 Slides • 15 Questions

1

Literal Equations Practice Problems

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3

Multiple Choice

Solve the equation for 'a'.


z=bm+az=b-m+a  

1

a=zb+ma=z-b+m  

2

a=zmba=z-m-b  

3

a=z+b+ma=z+b+m  

4

a=m+b+z a=-m+b+z\  

4

Multiple Choice

Solve the equation for x.

g=x+c+yg=x+c+y  



1

x=gcyx=-g-c-y  

2

x=gc+yx=-g-c+y  

3

x=cg+yx=c-g+y  

4

x=gcyx=g-c-y  

5

Multiple Choice

Solve the equation for 'a'.

am=pnam=pn  

1

a=mpma=-\frac{m}{pm}  

2

a=pnma=-pnm  

3

a=pnma=\frac{pn}{m}  

4

a=pnma=pnm  

6

Multiple Choice

Solve the equation for 'a'.

u=bkau=b-ka  


1

a=kukba=ku-kb  

2

a=ubka=\frac{-u-b}{k}  

3

a=u+bka=\frac{-u+b}{k}  

4

a=ku+ba=\frac{k}{-u+b}  

7

Multiple Choice

Solve the equation for 'x'.

u=xyku=\frac{xy}{k}  



1

x=ukyx=uk-y  

2

x=ukyx=\frac{uk}{y}  

3

x=yukx=-\frac{y}{uk}  

4

x=ukyx=-uky  

8

Multiple Choice

Solve the equation for 'a'.

ac=dr\frac{a}{c}=\frac{d}{r}  

1

a=rcda=-\frac{r}{cd}  

2

a=cd+ra=cd+r  

3

a=cdra=-\frac{cd}{r}  

4

a=cdra=\frac{cd}{r}  

9

Multiple Choice

Solve the equation for 'x'.

cx=rd\frac{c}{x}=rd  



1

x=crdx=\frac{c}{rd}  

2

x=rdcx=\frac{rd}{c}  

3

x=crdx=crd  

4

x=crdx=c-rd  

10

Multiple Choice

Solve the equation for 'x'.

cx=dr\frac{c}{x}=d-r  

1

x=cd+crx=cd+cr  

2

x=cd+rx=-\frac{c}{d+r}  

3

x=cdcrx=cd-cr  

4

x=cdrx=\frac{c}{d-r}  

11

12

Multiple Choice

What would this look like after removing 'x' from both terms (using backwards distributive...factoring)? 

4xy+3x-4xy+3x  

1

x(4+3)x(-4+3)

2

x(4y+3)x(-4y+3)

3

x(4y+3)x(4y+3)

4

x(y+3x)x(y+3x)

13

Multiple Choice

What would this look like after removing 'x' from both terms (using backwards distributive...factoring)? 

9cx+x9cx+x  

1

9(cx+x)9(cx+x)

2

c(9x+x)c(9x+x)

3

x(9c+1)x(9c+1)

4

x(9c)x(9c)

14

Multiple Choice

What would this look like after removing 'x' from both terms (using backwards distributive...factoring)? 

x+10bxx+10bx  

1

x(1+10b)x(1+10b)

2

x(10b)x(10b)

3

10(x+b)10(x+b)

4

b(x+10)b(x+10)

15

Multiple Choice

Solve the equation for 'x'.

z=5mx4yxz=-5mx-4yx  

1

x=z5m+4yx=\frac{z}{5m+4y}  

2

x=z5m4yx=\frac{z}{-5m-4y}  

3

x=z5m+4yx=-\frac{z}{-5m+4y}  

4

x=z5m4yx=-\frac{z}{-5m-4y}  

16

Multiple Choice

Solve the equation for 'x'.

u=4kx+yxu=-4kx+yx  

1

x=4uk+uyx=-4uk+uy  

2

x=u+4kyx=u+4k-y  

3

u4ky-\frac{u}{4k-y}  

4

x=4ukuyx=4uk-uy  

17

Multiple Choice

Solve the equation for 'x'.

u=4kxxu=-4kx-x  

1

x=u4k+1x=-\frac{u}{-4k+1}  

2

x=u4k1x=\frac{u}{-4k-1}  

3

x=4k+1ux=\frac{4k+1}{u}  

4

x=4k1ux=\frac{-4k-1}{u}  

18

Multiple Choice

Solve the equation for 'x'.

z=x+yxz=x+yx  

1

x=z1+yx=\frac{z}{1+y}  

2

x=z+1yx=-z+1-y  

3

x=z1yx=\frac{z}{1-y}  

4

x=1+yzx=\frac{1+y}{z}  

Literal Equations Practice Problems

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