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Solving a System of Equations Algebraically

Solving a System of Equations Algebraically

Assessment

Presentation

Mathematics

8th Grade

Practice Problem

Medium

CCSS
8.EE.C.8B, HSA.REI.C.6

Standards-aligned

Created by

Victoria Colbert

Used 14+ times

FREE Resource

7 Slides • 14 Questions

1

Solving a System of Equations Algebraically

Let's look at this puzzle quickly...

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2

Methods to solve:

  • Graphing

  • Substitution

  • Elimination

  • Calculator

3

Graphing

We have already done this.

4

Fill in the Blank

When solving for systems of linear equations graphically we look for the point of

5

Substitution

  • This is the method we will mostly use.

  • We get one variable by itself and then we SUBSTITUTE it's value into another equation with matching variables.

  • It is much easier to understand with a visual representation.

6

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7

Fill in the Blank

The point of intersection is written in (x,y) form. If x is 4, then the point of intersection for the last problem is (4,y). The value of y is

8

Elimination

  • Elimination can be the easiest way to solve systems.

  • The problem is that you must have the two equations in the exact same form.

  • This takes a bit of time to get the hang of, but once you do it can be so very easy to solve.

  • You still need to substitute at the end, so it doesn't save that step.

9

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10

Multiple Choice

Question image

Solve the given system by using substitution method.

1

Infinite number of solutions

2

x = 0, y = 7

3

x = -5, y = -7

4

x = 5, y = 7

5

no solution

11

Multiple Choice

Using Substitution, solve for the following system of linear equations:  y=2x+1y=2x+1  

x+y=16x+y=16  

1

(3,-7)

2

No solutions

3

Infinitely many solutions

4

(5,11)

12

Multiple Choice

Using Substitution, solve for the following system of linear equations:

y = 2x + 5

y = 4x + 9

1

(-2, 1)

2

(-2, -1)

3

(2, -1)

4

(2, 1)

13

Multiple Choice

Solve the given system by using substitution method:


x = 3y -13

4x + 2y = 4

1

x = 1, y = 4

2

x = -1, y = -4

3

x = -1, y = 4

4

x = 1, y = -4

14

Multiple Choice

Use elimination method to solve the system below.


4x + 8y = 20

-4x + 2y = -30

1

(-7,1)

2

(2,-5)

3

(-2,5)

4

(7,-1)

15

Multiple Choice

Solve by elimination:


4x + 4y = 4

3x + 4y = 10

1

x = 7,y = -6

2

x = -6, y = 7

3

x = 6, y = 7

4

x = 7, y = 6

16

Multiple Choice

Solve by elimination:


2x + 9y = -7

6x - 3y = 9

1

(-1, -1)

2

(2,-1)

3

(1,1)

4

(1,-1)

17

Multiple Choice

Using the elimination method, determine the solution to the system below.


x - y = 11

2x + y = 19

1

x = 10, y = -1

2

x = -1, y = 10

3

x = 3, y = -4

4

x = 6, y = 7

18

Multiple Choice

Solve:

x = -3y - 17

2x + 3y = -7

1

(1, -20)

2

(10, 0)

3

(-5, -2)

4

(10 , -9)

19

Multiple Choice

What is the solution to the system of equations?

y = 3x - 8

y = 4 - x

1

(3,1)

2

(1,3)

3

(3,-1)

4

(3,-1)

20

Multiple Choice

x - 3y = -13
4x + 2y = 4
1
(1, 4)
2
(-1, -4)
3
(-1, 4)
4
(1, -4)

21

Multiple Choice

Solve:
y = -1x - 5
4x - 8y = 4
1
(-3, -2)
2
(5, -7)
3
(3, 9)
4
(-5, 4)

Solving a System of Equations Algebraically

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