Limiting Reagents Review

Limiting Reagents Review

By Abby Fancsali

Practice Problem 1

Aluminum oxidizes according to the following equation:

4Al + 3O₂ → 2Al₂O₃

0.048 mol of Powdered Al is placed into a container containing 0.030 mol O2 .

How much Al₂O₃ can you make? What is the limiting reactant?

Multiple Choice

In order to find out how much we could make what do we need to find first

• The Theoretical yield From the Al

• The Theoretical yield From the O₂

• The Theoretical yield From the Al and the O₂

• The Percent Yield

Practice Problem 1

Aluminum oxidizes according to the following equation:

4Al + 3O₂ → 2Al₂O₃

0.048 mol of Powdered Al is placed into a container containing 0.030 mol O2 .

How much Al₂O₃ can you make?What is the limiting reactant?

​

Start with one of the substances:

​

• 0.0448 mol Al₂O₃

Multiple Choice

What should we do with our 0.048 mol Al

• Turn it in to grams

• Turn it into moles of Al₂O₃

• Tun it into Moles O₂

• Nothing, it is fine as it is

Practice Problem 1

Fill in the Blank

In theory, how many moles Al₂O₃ can you get out of 0.048 mol Al? **Give the exact answer as it appears on the calculator**

Practice Problem 1

Fill in the Blank

In theory, how many moles Al₂O₃ can you get out of 0.030 mol Al? **Give the exact answer as it appears on the calculator**

Practice Problem 1

Fill in the Blank

What is the total amount of moles of Al₂O₃ can you make from the given amounts?

Multiple Choice

Which reactant is your limiting reactant

• Al

• O₂

Practice Problem 2

2KBr(aq) + Cl₂(aq) → 2KCl(aq) + Br₂(l)

When 0.855 g of Cl2 and 3.205 g of KBr are mixed in solution, which is

the limiting reactant? How many grams of Br2 are formed?

​

​

​Step 1: turn our grams to moles

Fill in the Blank

When you have 0.855 grams of Cl₂, how many moles do you have? Round to three decimal places

Fill in the Blank

When you have 3.205 grams of KBr, how many moles do you have? Round to three decimal places

Practice Problem 2

2KBr(aq) + Cl₂(aq) → 2KCl(aq) + Br₂(l)

When 0.855 g of Cl2 and 3.205 g of KBr are mixed in solution, which is

the limiting reactant? How many grams of Br2 are formed?

​

​

​Step 1: turn our grams to moles

Step 2: Turn our moles of reactants into the product we want​

Fill in the Blank

How many moles of Br₂ Can you make from 0.855 grams of Cl₂ ?

Fill in the Blank

How many moles of Br₂ Can you make from 3.205 grams of KBr ?

Practice Problem 2

2KBr(aq) + Cl₂(aq) → 2KCl(aq) + Br₂(l)

When 0.855 g of Cl2 and 3.205 g of KBr are mixed in solution, which is

the limiting reactant? How many grams of Br2 are formed?

​

​

​Step 1: turn our grams to moles

Step 2: Turn our moles of reactants into the product we want​

Step 3: Compare our two amount of Br₂ and determine what is limiting​

Multiple Choice

What is the limiting Reactant

• KBr

• Cl₂

Practice Problem 2

2KBr(aq) + Cl₂(aq) → 2KCl(aq) + Br₂(l)

When 0.855 g of Cl2 and 3.205 g of KBr are mixed in solution, which is

the limiting reactant? How many grams of Br2 are formed?

​

​

​Step 1: turn our grams to moles

Step 2: Turn our moles of reactants into the product we want​

Step 3: Compare our two amount of Br₂ and determine what is limiting

Step 4: Turn the amount we can make into grams​

Fill in the Blank

How many grams of Br₂ can we make? Round to Two Decimal Places