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Advance Algebra with Trigonometry, Section 2-1: Linear Equations in One Variable

Advance Algebra with Trigonometry, Section 2-1: Linear Equations in One Variable

Assessment

Presentation

Mathematics

12th Grade

Practice Problem

Medium

CCSS
8.EE.C.7B

Standards-aligned

Created by

Jeremy Adelmann

Used 9+ times

FREE Resource

8 Slides • 9 Questions

1

Advance Algebra with Trigonometry

​Section 2-1: Linear Equations in One Variable

by Jeremy Adelmann

2

​Section 2-1 Objectives

​​Students will be able to:

  • ​Decide whether a number is a solution of a linear equation.

  • ​Solve linear equations by using the addition and multiplication properties of equality.

  • ​Solve linear equations by using the distributive property.

  • ​Solve linear equations with fractions or decimals.

  • ​Identify conditional equations, contradictions, and indentities.

3

​Objective 1: Decide whether a number is a solution of a linear equations.

​If the variable in an equation can be replaced with a real number that makes the statment true, the that number is a solution of the equation.

​7 is a solution for the equation 

​An equation is solved by finding its solution set. The solution set for this equation is {7}.

​If multiple equations have the same solution set, then they are Equivalent Equations. The solution set is {2}

4

​Objective 2: Solve linear adding and mutiplying

​Solve 5x - 3x - 6 = 14 + 8x + 4.

​The goal is to isolate the variable on one side of the equation.

​Combine Like Terms

Add 6 to both sides

Subtract 8x from both sides

​Divide both sides by -6

5

Fill in the Blank

Solve the equation.

5x+2 = 3x  65x+2\ =\ 3x\ -\ 6  

6

Fill in the Blank

Solve the equation.

9p+1=7p99p+1=7p-9  

7

Fill in the Blank

Solve the equation.

7x 5x +15=x+87x\ -5x\ +15=x+8  

8

Fill in the Blank

Solve the equation.

2x + 4 x=4x  52x\ +\ 4\ -x=4x\ -\ 5  

9

​Solving a Linear Equation in One Variable

  • ​Step 1: Clear Fractions - Eliminate any fractions by muliplying each side by the least common denominator.

  • ​Step 2: Simplify each side separately - Use distributive property to clear parantheses and combine like terms as needed.

  • ​Step 3: Isolate the variable terms on one side. Use the addition property to get all terms with variables on one side of the equation and all numbers on the other.

  • ​Step 4: Isolate the varaible - Use the multiplication property to get an equation with just the variable (coefficient of 1) on one side.

  • ​Step 5: Check - Substitute the proposed solution into the original equation.

10

​Objective 3: Using the Distibutive Property

​Solve 2(k - 5) + 3k = k + 6

  • ​Since there are no fractions, Step 1 does not apply.

Distributive Property

Multiply

Combine Like Terms

Add 10 to both sides

Subtract k from both sides

Divide both sides by 4

11

Fill in the Blank

Solve each equation.

3(2t4)=202t3\left(2t-4\right)=20-2t  

12

Fill in the Blank

Solve the equation.

2(32x)=x42\left(3-2x\right)=x-4  

13

Fill in the Blank

Solve the equation.

2(x+4)=4(x+1)2\left(x+4\right)=-4\left(x+1\right)  

14

​Obj. 4: Solving Linear Equations w/ Fractions

​Solve

​Start by eliminating the fractions. Multiply both sides by the LCD, 6.

​The LCD is 6.

​ Distributive Property

​ Multiply;

15

​Obj. 4: Solving Linear Equations w/ Fractions

​Distributive Property

​Multiply

​Combine Like Terms

​Add 17 to both sides

​Combine Like Terms

​Divide both sides by 7

16

Fill in the Blank

Solve the equation.

3x14+x+36=3\frac{3x-1}{4}+\frac{x+3}{6}=3  

17

Fill in the Blank

Solve the equation.

3x+27x+45=2\frac{3x+2}{7}-\frac{x+4}{5}=2  

Advance Algebra with Trigonometry

​Section 2-1: Linear Equations in One Variable

by Jeremy Adelmann

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