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Final Exam Review #7

Final Exam Review #7

Assessment

Presentation

Mathematics

9th - 12th Grade

Easy

CCSS
HSN.CN.A.2, HSN.CN.A.1, HSN.CN.C.8

Standards-aligned

Created by

Rhonda Prater

Used 8+ times

FREE Resource

3 Slides • 15 Questions

1

Final Exam Review #7

Add, Subtract, Multiply

Complex Numbers

Slide image

2

Adding and Subtracting Complex Numbers

Add all the real numbers together

Combine all the imaginary numbers (add coefficients)

Write answer in the form

a + bi

3

Multiple Choice

Add/Subtract:

(3 + i) + (-8 + 6i) - (-2 + 7i)

1

-3 + 14i

2

-3

3

3 + 14i

4

7 + 14i

4

Multiple Choice

Add/Subtract using the proper rules:

-3i + 2 - 4i + 16 - (4 - 8i)

1

22 - 15i

2

14 + i

3

14 - i

4

- 22 + 15i

5

Multiple Choice

Simplify: 
(10+ 15i) - (48 - 30i)
1
58 - 45i
2
58 - 15i
3
-38 - 15i
4
-38 + 45i

6

Multiple Choice

 2(3 + 4i)(4  6i)2\left(3\ +\ 4i\right)-\left(4\ -\ 6i\right)  

1

 2 + 14i2\ +\ 14i  

2

 10 + 2i10\ +\ 2i  

3

 1 2i-1\ -2i  

4

 2 2i-2\ -2i  

7

Multiple Choice

Simplify the expression:
 (5 + 4i)  (1  2i)\left(5\ +\ 4i\right)\ -\ \left(-1\ -\ 2i\right)  

1

 6 +6i6\ +6i  

2

 4 + 2i4\ +\ 2i  

3

 6  6i6\ -\ 6i  

4

 4  2i4\ -\ 2i  

8

Multiple Choice

Simplify the expression:
 (5 + 14i)  (10 + 2i)\left(5\ +\ 14i\right)\ -\ \left(10\ +\ 2i\right)  

1

 5 16i5\ -16i  

2

 5 + 16i-5\ +\ 16i  

3

 5  12i5\ -\ 12i  

4

 5 + 12i-5\ +\ 12i  

9

Multiple Choice

Simplify the expression:
 (8 + 9i) + (4  6i)\left(8\ +\ 9i\right)\ +\ \left(4\ -\ 6i\right)  

1

 17 + 3i17\ +\ 3i  

2

 12 + 3i212\ +\ 3i^2  

3

 17 2i17\ -2i  

4

 12 + 3i12\ +\ 3i  

10

Multiple Choice

Simplify the expression:
 (1 + 5i) + (1  5i)\left(1\ +\ 5i\right)\ +\ \left(1\ -\ 5i\right)  

1

 2 + 10i2\ +\ 10i  

2

 2 + 10i22\ +\ 10i^2  

3

 22  

4

 8-8  

11

Multiply Complex Numbers

 1=i                     i2=1\sqrt{-1}=i\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ i^2=-1  
Remember that each term in the first group needs to get distributed (multiplied) to each term in the second group.

(3 + i)(2 - i) =
3(2) +  3(-1i) +  1i(2)+ i(-i)  =
6 - 3i + 2i  -  i^2=
6 -1i - (-1) = 6 -1i +1=  

7-1i  or 7 - i

12

Multiple Choice

Another way to express √-1 is?

1

1

2

-1

3

i

4

0

13

Multiple Choice

What does i2 = ?
1
-1
2
√-1
3
1
4
-√1

14

Multiple Choice

(i)(3i)
1
-3i
2
-3
3
3
4
2i

15

Multiple Choice

(-4i)(3i)(4i)
1
24
2
-48i
3
48i
4
60

16

Multiple Choice

(-3-i)(6-i)
1
-21-7i
2
-19-3i
3
-15-5i
4
-17-9i

17

Multiple Choice

(7-5i)(7+5i)
1
74
2
75
3
74-1

18

Multiple Choice

(5-i)(5-i)
1
15-8i
2
36
3
24+10i
4
24-10i

Final Exam Review #7

Add, Subtract, Multiply

Complex Numbers

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