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Similarity in Right Triangles

Similarity in Right Triangles

Assessment

Presentation

Mathematics

9th - 10th Grade

Medium

CCSS
HSG.CO.C.9, 8.G.B.7, HSG.SRT.D.10

+2

Standards-aligned

Created by

Abby Kennedy

Used 53+ times

FREE Resource

12 Slides • 11 Questions

1

Similarity in Right Triangles

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2

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3

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Lets work this one together

4

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Lets work this one together

5

Multiple Choice

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Find x

1

15

2

12

3

9.9

4

6

6

Multiple Choice

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Find x

1

6.72

2

5

3

15

4

8.12

7

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8

Multiple Choice

Which one is the definition for geometric mean?

1

two positive numbers, a and b such that \frac{a}{x}=\frac{x}{b}

2

two positive numbers, a and b such that \frac{x}{a}=\frac{x}{b}

9

Let's do one together

6 and 30

10

Multiple Choice

16 and 28

1

447=87\sqrt{447}=8\sqrt{7}

2

180=65\sqrt{180}=6\sqrt{5}

3

.57

4

.57\sqrt{.57}

11

Multiple Choice

12 and 50

1

25

2

1050=32.40\sqrt{1050}=32.40

3

600=106\sqrt{600}=10\sqrt{6}

4

5

12

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13

Multiple Choice

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Which is the geometric mean for this triangle?

1

AD=BDDCAD=BD*DC

2

BD2=ADBCBD^2=AD\cdot BC

3

BD=ADBCBD=AD\cdot BC

4

BC=ADBDBC=AD*BD

14

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Let's do this one together!

15

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Let's do this one together!

16

Multiple Choice

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Find X.

1

1.2

2

270

3

21.6

4

3

17

Multiple Choice

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Find X.

1

30+14.7=44.7

2

51

3

14.7

4

30-21=9

18

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19

Multiple Select

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What is the geometric mean of this triangle using the Leg Theorem?



SELECT ALL THAT APPLY

1

 AB2=ADACAB^2=AD\cdot AC  

2

 ABAC=DCAB\cdot AC=DC  

3

 DC2=ABACDC^2=AB\cdot AC  

4

 BC2=DCACBC^2=DC\cdot AC  

20

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Let's do this one together

21

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Let's do this one together!

22

Multiple Choice

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Find X.

1

10\sqrt{10}

2

56=215\sqrt{56}=2\sqrt{15}

3

5656

4

72\sqrt{\frac{7}{2}}

23

Multiple Choice

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Find X.

1

56

2

56\sqrt{56}

3

252=67\sqrt{252}=6\sqrt{7}

4

10\sqrt{10}

Similarity in Right Triangles

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