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6.2 Inverse Functions and relations

6.2 Inverse Functions and relations

Assessment

Presentation

Mathematics

9th - 11th Grade

Medium

CCSS
HSF-BF.A.1B, HSF-BF.A.1C, HSF-BF.B.4B

Standards-aligned

Created by

Beth Knott

Used 9+ times

FREE Resource

17 Slides • 5 Questions

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6.2 Inverse Functions and relations

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Fill in the Blank

 f(x)=3x+2f\left(x\right)=3x+2  and  g(x)=2x21g\left(x\right)=2x^2-1  .  Find (g - f)(x)

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Fill in the Blank

 f(x)=3x+2f\left(x\right)=3x+2  and  g(x)=2x21g\left(x\right)=2x^2-1  .  Find  (fg)(x)\left(f\cdot g\right)\left(x\right)  

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Fill in the Blank

 f(x)=3x+2f\left(x\right)=3x+2  and  g(x)=2x21g\left(x\right)=2x^2-1  .  Find  (gf)(x)\left(g\circ f\right)\left(x\right)  

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Multiple Choice

 f(x)=x3f\left(x\right)=x-3  and  g(x)=x2g\left(x\right)=x^2 .  Evaluate  (fg)(1)\left(f\circ g\right)\left(1\right)   

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-2

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2

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6

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Find the inverse of

 f(x)=12x+1f\left(x\right)=-\frac{1}{2}x+1  

  • Step 1:  replace f(x) in the original equation with y

  •  y=12x+1y=-\frac{1}{2}x+1  

  • Step 2: interchange x and y

  •  x=12y+1x=-\frac{1}{2}y+1  

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  • Step 3: Solve for y

  •  x1=12yx-1=-\frac{1}{2}y  

  •  2(x1)=y-2\left(x-1\right)=y  

  • -2x+2=y

  • Step 4: Replace y with  f1(x)f^{-1}\left(x\right)  

  •  f1(x)=2x+2f^{-1}\left(x\right)=-2x+2  

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Original

 f(x)=13x+6f\left(x\right)=\frac{1}{3}x+6  

Inverse:  f1(x)=3x18f^{-1}\left(x\right)=3x-18  

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Find the inverse of the function graph the function and its inverse.  

 f(x)=x2+1f\left(x\right)=x^2+1  

  •  y=x2+1y=x^2+1  

  •  x=y2+1x=y^2+1  

  •  x1=y2x-1=y^2  

  •  y=±x1y=\pm\sqrt{x-1}  

  •  f1(x)=±x1f^{-1}\left(x\right)=\pm\sqrt{x-1}  

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 f(x)=x2+1f\left(x\right)=x^2+1  

  • that is a parabola you know how to graph

  • But how to graph a square root function?

  • Remember that its the inverse.  That means the x and y values were interchanged!

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Determine whether f(x) and g(x) are inverses of each other.

 f(x)=34x6f\left(x\right)=\frac{3}{4}x-6  and  g(x)=43x+8g\left(x\right)=\frac{4}{3}x+8  

  • You must show  (fg)(x)=x\left(f\circ g\right)\left(x\right)=x   AND  (gf)(x)=x\left(g\circ f\right)\left(x\right)=x  

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 (fg)(x)=x\left(f\circ g\right)\left(x\right)=x  

  •  f(43x+8)=xf\left(\frac{4}{3}x+8\right)=x  

  •  34(43x+8)6=x\frac{3}{4}\left(\frac{4}{3}x+8\right)-6=x  

  •  x+66=xx+6-6=x  

  • x=x

  • YOU ARE ONLY HALF DONE.  NOW  (gf)(x)=x\left(g\circ f\right)\left(x\right)=x  

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 (gf)(x)=x\left(g\circ f\right)\left(x\right)=x  

  •  g(34x6)=xg\left(\frac{3}{4}x-6\right)=x  

  •  43(34x6)+8=x\frac{4}{3}\left(\frac{3}{4}x-6\right)+8=x  

  •  x8+8=xx-8+8=x  

  •  x=xx=x  

  • Yes, f(x) and g(x) are inverse of each other

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Multiple Choice

Determine whether f(x)=3x1f\left(x\right)=3x-1  and  g(x)=x13g\left(x\right)=\frac{x-1}{3}  are inverses of each other.  Use composition of functions.


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Yes

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No

6.2 Inverse Functions and relations

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