
Geometry Review / Flashcard - 6th grade
Flashcard
•
Mathematics
•
6th Grade
•
Hard
Eddie Coverson
FREE Resource
Student preview

20 questions
Show all answers
1.
FLASHCARD QUESTION
Front
The base and height of a parallelogram must be...
Back
perpendicular
Answer explanation
The base and height of a parallelogram must be perpendicular to each other. This ensures that the height is measured straight up from the base, allowing for accurate area calculation.
2.
FLASHCARD QUESTION
Front
Find the area of the parallelogram.
Back
80
Answer explanation
The area of a parallelogram is calculated using the formula: Area = base × height. If the base is 10 and the height is 8, then Area = 10 × 8 = 80. Thus, the correct answer is 80.
3.
FLASHCARD QUESTION
Front
Area of the parallelogram?
Back
77 m2
Answer explanation
To find the area of a parallelogram, use the formula: Area = base × height. Given the dimensions, the calculation yields 77 m², making this the correct answer.
4.
FLASHCARD QUESTION
Front
How do you find the AREA of a TRIANGLE?
Back
base x height divided by 2
Answer explanation
To find the area of a triangle, use the formula: (base x height) divided by 2. This accounts for the triangle's shape, as it is half of a rectangle formed by the base and height.
5.
FLASHCARD QUESTION
Front
What is the area of this triangle?
Back
6 sq. cm.
Answer explanation
To find the area of a triangle, use the formula: Area = 1/2 * base * height. If the base is 4 cm and height is 3 cm, then Area = 1/2 * 4 * 3 = 6 sq. cm. Thus, the correct answer is 6 sq. cm.
6.
FLASHCARD QUESTION
Front
Find the area of the triangle.
Back
28 cm2
Answer explanation
To find the area of a triangle, use the formula: Area = 1/2 * base * height. Given the dimensions, the calculation yields 28 cm², making this the correct choice among the options.
7.
FLASHCARD QUESTION
Front
A flat "unfolded" representation of a prism or pyramid is called .......
Back
Net
Answer explanation
A flat "unfolded" representation of a prism or pyramid is called a "Net". It shows all the faces of the 3D shape laid out in 2D, making it easier to visualize the surface area and dimensions.
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