$$4\ \frac{2}{3}+3\ \frac{1}{4}\ =$$

$$\frac{13}{3}+\frac{13}{4}=\frac{56}{12}+\frac{39}{12}=\frac{95}{12}=7\ \frac{11}{12}$$

Write in order of smallest to largest $$0.0078,\ \ 0.78,\ \ 0.87,\ \ 0.708$$

$$0.0078,\ \ 0.708,\ \ 0.78,\ \ 0.87$$

$$2\ \frac{1}{7}+1\ \frac{1}{4}$$

$$=\frac{15}{7\ }+\frac{5}{4}\ =\frac{60}{28}+\frac{35}{28}=\frac{95}{28}$$

$$1\ \frac{1}{5}\div\ \frac{3}{4}$$

$$=\frac{6}{5}\div\ \frac{3}{4}=\frac{6}{5}\times\ \frac{4}{3}=\frac{24}{15\ }=\frac{8}{5}=1\ \frac{3}{5}$$

$$3\ \frac{1}{2}-1\ \frac{3}{4}$$

$$=\frac{7}{2}-\frac{7}{4}=\frac{14}{4}-\frac{7}{4}=\frac{7}{4}=1\ \frac{3}{4}$$

Find the size of one angle in a regular pentagon

$$\frac{\left(\left(5-2\right)\times\ 180\right)}{5}=108\degree\ $$

Find the sum of the interior angles in a 12 sided shape

$$\left(12-2\right)\text{}\times\ 180\ =1800$$

What is the formula for the sum of interior angles of a polygon?

$$\left(n-2\right)\text{}\times\ 180$$

The size of each interior angle in a regular polygon is $$165\degree$$ . Find out how many sides it has.

To get exterior angle: 180-165 = 15 $$360\div\ 15\ =12$$

Find the area of this trapezium

8+11 = 19 19/2 = 9.5 9.5 x 4 = 38

Find the volume of the prism

Area of Cross-section: 4 x 5 = 20 20\2 = 10 Volume: 10 x 12 = 120

Foundation Maths GCSE Flashcards

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