Flashcard: Probability

Flashcard: Probability

Assessment

Flashcard

Mathematics

University

Practice Problem

Medium

Created by

Hafizah F

Used 2+ times

FREE Resource

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20 questions

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1.

FLASHCARD QUESTION

Front

Define the terms experiment, sample space, and event in probability theory with examples.

Back

  • Experiment: A process that leads to an outcome (e.g., rolling a die).

  • Sample Space (S): The set of all possible outcomes (e.g., {1,2,3,4,5,6} for a die).

  • Event (E): A subset of the sample space (e.g., rolling an even number {2,4,6}).

2.

FLASHCARD QUESTION

Front

A game involves rolling two six-sided dice. Define the sample space and find the probability of the following events:

  1. 1. Getting a sum of 8.

  2. 2. Rolling a double (both dice show the same number).

Back

  • Sample Space (S): Since each die has 6 sides, the total number of outcomes is 6 × 6 = 36.

  • Event 1: Sum of 8

  • (2,6),(3,5),(4,4),(5,3),(6,2) → 5 outcomes.

    • Probability: 5/36 = 0.139

  • Event 2: Rolling a Double

  • (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) → 6 outcomes.

    • Probability: 6/36=0.167366

3.

FLASHCARD QUESTION

Front

In a class of 40 students, 25 like Mathematics, and 15 like Science. If a student is chosen randomly, what is the probability they like Mathematics?

Back

P(Mathematics)=25/40​=0.625

4.

FLASHCARD QUESTION

Front

How many ways can you arrange 5 different books on a shelf?

Back

5!=5×4×3×2×1=120.

5.

FLASHCARD QUESTION

Front

There are eight identical flags which consists of two reds, four blues and two yellows.

If all of them are to be hung up to make a signal, calculate how many distinguishable signals are there for each of the following:
a. There are no preferences.
b. The blues must be together.

Back

a. 8!/(2! 4! 2!) = 420

b. 5! / (2! 2!) = 30

6.

FLASHCARD QUESTION

Front

How many different ways can you arrange the letters of the word "SUCCESS"?

Back

7!/(3!2!)​=420

7.

FLASHCARD QUESTION

Front

If events A and B are mutually exclusive, what is P(A∪B)?

Back

P(A∪B)=P(A)+P(B)

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