What is the sum formula for tangent?
Sum/Difference & Double Angle Formulas

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Mathematics
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10th - 12th Grade
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Hard
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1.
FLASHCARD QUESTION
Front
Back
The sum formula for tangent is: tan(α + β) = \frac{tan α + tan β}{1 - tan α * tan β}
2.
FLASHCARD QUESTION
Front
What is the difference formula for tangent?
Back
The difference formula for tangent is: tan(α - β) = \frac{tan α - tan β}{1 + tan α * tan β}
3.
FLASHCARD QUESTION
Front
What is the double angle formula for sine?
Back
The double angle formula for sine is: sin(2θ) = 2 * sin(θ) * cos(θ)
4.
FLASHCARD QUESTION
Front
What is the double angle formula for cosine?
Back
The double angle formula for cosine is: cos(2θ) = cos²(θ) - sin²(θ) or cos(2θ) = 2 * cos²(θ) - 1 or cos(2θ) = 1 - 2 * sin²(θ)
5.
FLASHCARD QUESTION
Front
What is the Pythagorean identity?
Back
The Pythagorean identity states that: sin²(θ) + cos²(θ) = 1
6.
FLASHCARD QUESTION
Front
How do you find sin(105°) using sum formulas?
Back
To find sin(105°), use the sum formula: sin(105°) = sin(60° + 45°) = sin(60°)cos(45°) + cos(60°)sin(45°) = \frac{\sqrt{3}}{2} * \frac{\sqrt{2}}{2} + \frac{1}{2} * \frac{\sqrt{2}}{2} = \frac{\sqrt{6} + \sqrt{2}}{4}.
7.
FLASHCARD QUESTION
Front
What is the value of sin(2θ) if cos(θ) = 4/5 and 270° < θ < 360°?
Back
Using the double angle formula: sin(2θ) = 2 * sin(θ) * cos(θ). First, find sin(θ) using the Pythagorean identity: sin²(θ) = 1 - cos²(θ) = 1 - (4/5)² = 9/25, so sin(θ) = -3/5 (since θ is in the fourth quadrant). Thus, sin(2θ) = 2 * (-3/5) * (4/5) = -24/25.
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