Exponential Growth & Decay

Exponential Growth & Decay

Assessment

Flashcard

Mathematics

9th - 12th Grade

Hard

CCSS
HSF-IF.C.8B, HSF.BF.A.2, HSF-IF.C.7E

+1

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is Exponential Growth?

Back

Exponential Growth occurs when a quantity increases by a fixed percentage over a period of time, resulting in a rapid increase. For example, if a population grows by 20% each year, it will grow faster each subsequent year.

Tags

CCSS.HSF-LE.A.1A

2.

FLASHCARD QUESTION

Front

What is Exponential Decay?

Back

Exponential Decay is the process where a quantity decreases by a fixed percentage over time. For example, if a substance decays at a rate of 10% per year, it will lose 10% of its remaining amount each year.

Tags

CCSS.HSF-IF.C.8B

3.

FLASHCARD QUESTION

Front

What is the formula for Exponential Growth?

Back

The formula for Exponential Growth is y = a(1 + r)^t, where 'a' is the initial amount, 'r' is the growth rate (as a decimal), and 't' is the time period.

Tags

CCSS.HSF-IF.C.8B

4.

FLASHCARD QUESTION

Front

What is the formula for Exponential Decay?

Back

The formula for Exponential Decay is y = a(1 - r)^t, where 'a' is the initial amount, 'r' is the decay rate (as a decimal), and 't' is the time period.

Tags

CCSS.HSF-IF.C.8B

5.

FLASHCARD QUESTION

Front

How do you calculate the future value in Exponential Growth?

Back

To calculate the future value in Exponential Growth, use the formula: Future Value = Initial Amount * (1 + Growth Rate)^Number of Periods.

Tags

CCSS.HSF-IF.C.8B

6.

FLASHCARD QUESTION

Front

How do you calculate the future value in Exponential Decay?

Back

To calculate the future value in Exponential Decay, use the formula: Future Value = Initial Amount * (1 - Decay Rate)^Number of Periods.

Tags

CCSS.HSF-IF.C.8B

7.

FLASHCARD QUESTION

Front

If a population of 100 increases by 50% each year, how many will there be after 2 years?

Back

After 2 years, the population will be 100 * (1 + 0.5)^2 = 225.

Tags

CCSS.HSF.BF.A.2

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