Unit 5 Test Review

Front

Solve for x: x^2 - 2.25 = 0

Back

x = ±1.5

Front

Determine the number of solutions to the linear-quadratic system: y = x^2 and y = 2x - 1

Back

2 solutions

Front

What are the zeros of the function f(x) = x^2 - 4?

Back

x = 0 and x = 4

Front

If the discriminant is positive (b^2 - 4ac > 0), what can be said about the quadratic equation?

Back

It has 2 Real Solutions.

Front

For the function f(x) = x^2 - 4x + 4, is the discriminant positive, negative, or zero?

Back

Zero

Front

What is the definition of a quadratic function?

Back

A function of the form f(x) = ax^2 + bx + c, where a ≠ 0.

Front

What does the discriminant tell us about a quadratic equation?

Back

It indicates the nature of the roots (real and distinct, real and equal, or complex).

Front

How do you find the vertex of a quadratic function in standard form?

Back

Use the formula x = -b/(2a) to find the x-coordinate, then substitute back to find the y-coordinate.

Front

What is the vertex of the quadratic function f(x) = 2x^2 - 8x + 6?

Back

Vertex is (2, -2).

Front

What is the axis of symmetry for the quadratic function f(x) = x^2 + 6x + 8?

Back

x = -3.