1st Period Quadratic area problems

Front

What is the formula for the area of a rectangle?

Back

Area = Length × Width

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

Front

If the length of a rectangle is 3 times its width, how can you express the length in terms of width?

Back

Length = 3 × Width

Tags

CCSS.6.EE.C.9

Front

A rectangle has an area of 48 square units. If the width is 4 units, what is the length?

Back

Length = 12 units (Area = Length × Width => 48 = Length × 4 => Length = 12)

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

Front

What is the relationship between the length and width of a rectangle if the width is 5 times the length?

Back

Width = 5 × Length

Tags

CCSS.6.EE.C.9

Front

If a rectangle has an area of 500 square feet and the width is 5 times the length, what is the length?

Back

Length = 10 feet (Area = Length × Width => 500 = Length × 5 × Length => Length^2 = 100 => Length = 10)

Front

How do you set up an equation to find the dimensions of a rectangle when given the area and a relationship between length and width?

Back

Use the formula Area = Length × Width and substitute the relationship into the equation.

Tags

CCSS.8.EE.C.7B

Front

What is the area of a rectangle with a length of 20 units and a width of 10 units?

Back

Area = 200 square units (Area = Length × Width => 20 × 10 = 200)

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

Front

If the area of a rectangle is 336 square yards and the width is 5 yards longer than the length, how do you express the width?

Back

Width = Length + 5 yards

Front

What are the dimensions of a rectangle if the area is 336 square yards and the width is 21 yards?

Back

Length = 16 yards, Width = 21 yards (Area = Length × Width => 336 = 16 × 21)

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

Front

What is the first step to solve a problem involving the area of a rectangle?

Back

Identify the relationship between length and width and set up the area equation.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3