Solving Logarithmic Equations

Solving Logarithmic Equations

Assessment

Flashcard

Mathematics

11th - 12th Grade

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

Student preview

quiz-placeholder

15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the definition of a logarithm?

Back

A logarithm is the exponent to which a base must be raised to produce a given number. For example, log_b(a) = c means b^c = a.

2.

FLASHCARD QUESTION

Front

What is the change of base formula for logarithms?

Back

The change of base formula states that log_b(a) = log_k(a) / log_k(b) for any positive k.

3.

FLASHCARD QUESTION

Front

How do you solve the equation log_x(1000) = 3?

Back

To solve log_x(1000) = 3, rewrite it in exponential form: x^3 = 1000. Therefore, x = 10.

4.

FLASHCARD QUESTION

Front

What is the property of logarithms that states log_b(mn) = ?

Back

log_b(m) + log_b(n). This property states that the logarithm of a product is the sum of the logarithms.

5.

FLASHCARD QUESTION

Front

What is the property of logarithms that states log_b(m/n) = ?

Back

log_b(m) - log_b(n). This property states that the logarithm of a quotient is the difference of the logarithms.

6.

FLASHCARD QUESTION

Front

What is the property of logarithms that states log_b(m^n) = ?

Back

n * log_b(m). This property states that the logarithm of a power is the exponent times the logarithm of the base.

7.

FLASHCARD QUESTION

Front

How do you solve log_2(x^2 - 6) = log_2(2x + 2)?

Back

Since the logs are equal, set the arguments equal: x^2 - 6 = 2x + 2. Rearranging gives x^2 - 2x - 8 = 0, which factors to (x - 4)(x + 2) = 0, so x = 4 or x = -2.

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?