Chain Rule and Implicit

Front

Find dy/dx
xy+y²=2

Back

-y/(x+2y)

Front

Find dy/dx by Implicit Differentiation
2xy³ - x²y = 2

Back

2y(x-y²)/x(6y²-x)

Front

Find the derivative: y=(2^3x+4)

Back

3(ln2)(2^3x+4)

Front

What is the derivative?

Back

(3x)/(2(3x²+5))

Front

Find f'(x)
f(x) = cos²(3x)/(9x⁴-6)

Back

[-6(9x⁴-6)cos(3x)sin(3x) - 36x³cos²(3x)]/(9x⁴-6)²