

Chapter 6/17 Thermodynamics MCQ Assessment
Flashcard
•
Chemistry
•
9th - 12th Grade
•
Practice Problem
•
Hard
Wayground Content
FREE Resource
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16 questions
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1.
FLASHCARD QUESTION
Front
What is the standard entropy change (ΔS°) for a reaction?
Back
The standard entropy change (ΔS°) for a reaction is calculated using the formula: ΔS° = ΣS°(products) - ΣS°(reactants). It indicates the change in disorder or randomness in a system.
2.
FLASHCARD QUESTION
Front
How do you calculate the standard entropy change for the reaction: 2Cu(s) + O2(g) → 2CuO(s)?
Back
ΔS° = [2 * S°(CuO)] - [2 * S°(Cu) + S°(O2)] = [2 * 42.5] - [2 * 33.15 + 205.14] = -93.22 J/K·mol.
3.
FLASHCARD QUESTION
Front
What drives spontaneous reactions?
Back
Spontaneous reactions are driven by decreasing enthalpy (ΔH) and increasing entropy (ΔS).
4.
FLASHCARD QUESTION
Front
What is Gibbs free energy (ΔG) and how is it calculated?
Back
Gibbs free energy (ΔG) is a thermodynamic potential that measures the maximum reversible work obtainable from a thermodynamic system at constant temperature and pressure. It is calculated using the formula: ΔG = ΔH - TΔS.
5.
FLASHCARD QUESTION
Front
Calculate ΔG° at 298 K for the combustion of methane: CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g).
Back
ΔG° = [ΔG°(CO2) + 2 * ΔG°(H2O)] - [ΔG°(CH4) + 2 * ΔG°(O2)] = [-394.4 + 2 * (-228.57)] - [-50.8 + 0] = -801 kJ.
6.
FLASHCARD QUESTION
Front
What is specific heat capacity?
Back
Specific heat capacity is the amount of heat required to raise the temperature of one gram of a substance by one degree Celsius (°C).
7.
FLASHCARD QUESTION
Front
How much heat does an aluminum block absorb if 10.00 grams are heated from 25.0°C to 50.0°C?
Back
Heat absorbed (q) = mass * specific heat * change in temperature = 10.00 g * 0.900 J/g°C * (50.0 - 25.0)°C = 225 J.
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