AP Physics Friction

Front

A skier is going down a slope at constant speed. The coefficient of friction between the skier and the incline is .61. Find the angle of inclination.

Back

31^o

Front

What type of friction is not moving?

Back

static

Front

How can friction be reduced?

Back

All of the above are ways of reducing friction: reduce the force acting between the 2 surfaces, reduce the roughness of the 2 surfaces coming in contact, use wax, grease or oil.

Front

What is the coefficient of static friction if it takes 44 N of force to move a box that weighs 86 N?

Back

0.51

Front

As the angle of the incline increases, what happens to the normal force?

Back

The normal force decreases

Front

Given the FBD, which of the following must be true?

• The frictional force must be accelerating the system to the left.
• The box must be accelerating to the right.
• The box must be moving to the right.
• The FBD is incorrectly drawn. This situation isn't possible.

Back

The FBD is incorrectly drawn. This situation isn't possible.

Front

Which of the following is true about the system shown? Options: The system is not accelerating., The tension between m₂ and m₁ is less than the tension between m₂ and m₃, The acceleration of the system only depends on m₃, None of the other answers are true

Back

The tension between m₂ and m₁ is less than the tension between m₂ and m₃

Front

Which of the following is not true about the system?

• T₃ is equal to the scalar sum of the magnitudes of T₂ and T₁
• T₃ is equal in magnitude to F_g
• The x- components of the T₁ and T₂ and equivalent but in opposite directions
• The system is in equilibrium.

Back

T₃ is equal to the scalar sum of the magnitudes of T₂ and T₁

Front

If there is no friction, then the acceleration would be equal to: mg, sin(θ)mg, g, sin(θ)g

Back

sin(θ)g

Front

If μ_k = 0.65 and μ_s = 0.7, acceleration would be equal to

Back

0 m/s/s