A8A Flashcard 1: Solving quadratics

Front

What should you do first in solving this equation?
x² + 6x - 13 = 3

Back

Make it equal 0 by subtracting 3 on each side

Front

What is the standard form for a Quadratic? Options: ax²+ bx = - c, x = -b ± √(b²-4ac) / 2a, ax² + bx + c, y = mx + b

Back

ax² + bx + c

Front

Solve the equation using square roots.
x² = 121

Back

± 11

Front

Solve the equation using the zero product property.
(x- 9)(x + 3) = 0

Back

x = -3 or x = 9

Front

What are the zeros?

Back

x= 0 and x= 4

Front

True or false: The solutions, roots, x-intercepts, and zeros of a quadratic equation are all the same thing.

Back

True

Front

Factors and solutions of x² + 2x – 3 = 0

Back

Factors: (x - 1)(x + 3); Solutions: x=1, x=-3

Front

4x²+12x=135

Back

4.5

Front

5x²-36x+36 = 0

Back

x = 1.2

Front

What are the solutions to (x+7)²=81?

Back

-16 and 2