Solving Systems of Equations by Substitution

Front

y = -6x - 2

y = 4x - 12

Back

(1, -8)

Front

Solve the system of equations:

y = -5x + 16

3x + 5y = -8

Back

(-1, 2)

Front

y = -5x - 14

y = 5x + 6

Back

(-2, -4)

Front

Solve for x in the equation:

-6x + 4y = 12

y = 6

Back

(2, 6)

Front

y = 5x + 7

8x - 8y = -24

Back

(4, -4)

Front

y = 2x - 6

y = -5x + 15

Options: (3, -1), (3, 2), (3, 0), (3, 11)

Back

(3, 0)

Front

4x + 2y = 12

y = 3x - 14

Back

(4, -2)

Front

Solve the system of equations:

8x - 6y = 0

y = 3x + 5

Back

(-3, -4)

Front

y = -4x + 17

y = -5x + 23

Options: (6, -7), (4, -6), (6, 4), (6, -4)

Back

(6, -7)

Front

7x - 5y = -5

y = -4x + 1

Back

(0, 1)